Mathematics, 03.10.2019 02:40 Undrea43

The equation of the graphed line in point-slope form is what

y-0=-3/5(x-3)

3y=-5(x-3)

y-3=-3/5(x-0)

and it’s equation in slope-intercept form is what

y=-9/5x+3/5

5y=-3(x-3)

y=-3/5x+9/5

The equation of the graphed line in point-slope form is what y-0=-3/5(x-3) 3

Answers: 1

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The equation of the graphed line in point-slope form is what

y-0=-3/5(x-3)

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The equation of the graphed line in point-slope form is what y-0=-3/5(x-3) 3y=-5(x-3) y-3=-3/5(x-0) and it’s equation in slope-intercept form is what y=-9/5x+3/5 5y=-3(x-3) y=-3/5x+9/5

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Other questions on the subject: Mathematics

Questions in other subjects:

The equation of the graphed line in point-slope form is what

y-0=-3/5(x-3)

3y=-5(x-3)

y-3=-3/5(x-0)

and it’s equation in slope-intercept form is what

y=-9/5x+3/5

5y=-3(x-3)

y=-3/5x+9/5