The formula for the volume of a cylinder with a height of 5 units is v(r)=5(3.14)r^2 where r is the radius of the cylinder. in which quadrant(s) is the graph of this function v(r)?

The graph of this function V(r) is in the I (first) quadrant.

Solution:

V(r)=5(3.14)r^2

V(r)=15.7r^2

The graph of this function is a parabola with vertex at the origin and opens upward (I and II quadrants), but the radius is a positive number (right to the y-axis), then the graph of this function is in the I (first) quadrant.

do you mean add both of the equations together

because if you do the answer is 10x-5

step-by-step explanation:

find the magnitude of the trig term  

csc

(

x

)

−

1

by taking the absolute value of the coefficient.

1

find the lower bound of the range.

tap for more

y

=

−

2

find the upper bound of the range.

tap for more

y

=

0

the range is  

y

≤

−

2

or  

y

≥

0

.

(

−

∞

,

−

2

]

∪

[

0

,

∞

)

{

y

|

y

≤

−

2

,

y

≥

0

}

step-by-step explanation: