The point-slope form of the equation of the line that passes through (–4, –3) and (12, 1) is y – 1 = (x – 12). what is the standard form of the equation for this line?

                   y - 1 = 0.25(x - 12)
                   y - 1 = 0.25(x) - 0.25(12)
                   y - 1 = 0.25x - 3
                     + 1             + 1
                        y = 0.25x - 2
          -0.25x + y = 0.25x - 0.25x + 2
          -0.25x + y = 2
    -1(-0.25x + y) = -1(2)
-1(-0.25x) - 1(y) = -2
           0.25x - y = -2

-2x + 7 = 7

subtract 7 from both sides.

-2x = 0

divide both sides by -2.

x = 0

the value of x is equal to 0.