Mathematics, 01.08.2019 23:00 Andy10201

Aboat drops an anchor 75 feet to the bottom of a lake. a sunken treasure chest lies at the bottom of the lake, 40 feet away from the anchor. what is the distance from the boat to the treasure chest ?

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Given
Height (length) of the anchor dropped from the boat = 75 feet
Distance of the treasure from the anchor = 40 feet

Solution
The dropped at the bottom makes an angle of 90 degree . Therefore making an right triangle with the chest and boat

By Pythagoras theorem
AC^2 = AB^2 + BC^2

(AC = distance of the treasure from the boat
AB = height of the anchor dropped from the boat
BC = the distance of treasure from the anchor)

AC^2 = 75^2 + 40^2
AC^2 = 5325 +1600
AC^2 = 6925
AC = 25 * (under root 11)

Therefore they have cover a distance of 25 * (under root 11)

Answer from: Chantamariepaul

Answer from: Quest

all group life insurance is term insurance. actually it is annual renewable term and it is rated on the average age and claims experience of the entire group, which is called "experience rating." remember, this type of insurance has a 31-day grace period and is convertible to whole life upon leaving employment. a contributory group plan requires that both the employer and the employees pay part of the premium. at least 75% of those eligible must participate, so the group is sure to get most of the healthy employees as well as those that are sick.

step-by-step explanation:

Answer from: Quest

The correct answer is 7

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Aboat drops an anchor 75 feet to the bottom of a lake. a sunken treasure chest lies at the bottom of...