Anyone able to me on these problems?

9)

Using intercept theorem

15/23 = TU/69

Multiplying both sides by 69, we get

15 ×69/23=TU

TU = 45

Similarly

23/36 =69/VW

Cross multiplying

23 VW = 36 × 69

Dividing by 23 on both sides

VW = 108

Now TW = 45 + 69 + 108

TW = 222

10)

VY= 34, YW = 6

So VW = 34 + 6 = 40

Using similarity we get

VY/VW = YZ/WX

34/40= 51/(2x²+10)

Cross multiplying

34(2x²+10) = 51 ×40

Dividing by 34 on both sides

2x² + 10 = 60

Subtracting 10

2x² = 50

x² = 25

x = 5

So WX = 2x² + 10 = 2(5)²+10 = 60

11)

By similarity

OE/OF = OG/OH

18/12 = 12/OH

Cross multiplying

18OH = 12 ×12

18OH =144

OH = 8

But H is on the negative X axis

So H(-8,0)

12)

From figure using similarity

x/187 = 620/220

Multiplying both sides by 187

We get

x = 527 ft

13)

Using angle bisector theorem

KJ/KL = JM/ML

x/63 = 28/x

Cross multiplying

x² = 63 ×28

x² = 1764

Taking square root

x = 42

So

Perimeter = 42 + 28 + 42 + 63

Perimeter = 175 units

1/3

step-by-step explanation:

to find this, you can divide 12 by 4 which is 3 or you can multiply 4 until you reach 12 (4x3=12). both should give you 3, meaning theres three times less bananas than there are oranges.

it would take 7/10 of an hour too fill the pool.

step-by-step explanation: