The work of a student to solve the equation 2(6y − 3) = 20 + 6y is shown below:
step 1:...
Mathematics, 25.10.2019 11:43 colin5514
The work of a student to solve the equation 2(6y − 3) = 20 + 6y is shown below:
step 1: 2(6y − 3) = 20 + 6y
step 2: 8y − 5 = 20 + 6y
step 3: 2y − 5 = 20
step 4: 2y = 25
step 5: y = 12.5
in which step did the student first make an error and what is the correct step?
step 2: 8y-5=10+3y
step 2: 12y-6=20+6y
step 3: 6y-3=2(18+3y)
step 3: 2(6y-3)=18+3y
Answers: 1
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