Two samples were taken of fish caught on small lake and are shown in the table below. it is estimated that the small lake fish population is roughly 1,000 fish. what is the average number of brown trout in the lake? small lake fish sample sample 1 sample 2 rainbow trout 15 rainbow trout 11 brown trout 3 brown trout 1 largemouth bass 9 largemouth bass 11 43 80 160 333

80

Step-by-step explanation:

In the first sample, there were a total of

15+3+9 = 27 fish.

In the second sample, there were a total of

11+1+11 = 23 fish.

This is a total of 27+23 = 50 fish.

Out of those 50 fish, 3+1 = 4 were brown trout.  This is an experimental probability of 4/50.  

Multiplying this by the 1000 fish in the lake, we have

4/50(1000) = 4/50(1000/1) = 4000/50 = 80

The answer is B -80

Step-by-step explanation:

i would pic false cause it goes down towards negative

step-by-step explanation:

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116