Arocket is launched vertically from the ground with an initial velocity of 64 ft/sec. write a quadratic function h(t) that shows the height, in feet, of the rocket t seconds after it was launched.

The kinematics equation of motion: h(t)=ut+(1/2)at& sup2; where u=initial velocity (+ve upwards)a=acceleration,     due to gravity, a=-g=-32.2 ft/s²  t=time in secondssubstituting u=64 ft/s²h(t)=64t-(1/2)(32.2)t²=> h(t)=64t-16.1t²note: sometime g=-32ft/s² is used

What am i doing here. add?