Members of a school social service group hold a spaghetti dinner to raise money for orphan children. they must sell tickets at a price that will earn them more money than the cost of food. the formula for this scenario is t = n (p − c) where t = total profit earned from the event c = cost of food per plate n = number of tickets sold p = price charged for each dinner rewrite the equation to determine the number of tickets they need to sell.

Step-by-step explanation:

The problem asks to rewrite the equation to solve for the number of tickets sold, which is represented by the variable n. This means one must isolate n

{x = -1/2 ,   y = -1

step-by-step explanation:

solve the following system:

{2 x + y = -2

{10 x - 3 y = -2

in the first equation, look to solve for y:

{2 x + y = -2

{10 x - 3 y = -2

subtract 2 x from both sides:

{y = -2 x - 2

{10 x - 3 y = -2

substitute y = -2 x - 2 into the second equation:

{y = -2 x - 2

{10 x - 3 (-2 x - 2) = -2

10 x - 3 (-2 x - 2) = (6 x + 6) + 10 x = 16 x + 6:

{y = -2 x - 2

{16 x + 6 = -2

in the second equation, look to solve for x:

{y = -2 x - 2

{16 x + 6 = -2

subtract 6 from both sides:

{y = -2 x - 2

{16 x = -8

divide both sides by 16:

{y = -2 x - 2

{x = -1/2

substitute x = -1/2 into the first equation:

{y = -1

{x = -1/2

collect results in alphabetical order:

answer:   {x = -1/2 ,   y = -1

x=-7

step-by-step explanation:

x+3=-10

-10+3=-7

x=-7