The sum of three consecutive integers is 345. find the three integers.

Our three consecutive integers can be represented as

X ← first integer

X + 1 ← second integer

X + 2 ← third integer

Since the sum of our three consecutive integers is 345, our equation will read

X + X + 1 + X + 2 = 345

When we simplify on the left, our equation will now read

3x + 3 = 345

      -3      -3  ← subtract 3 on both sides

      3x = 342 ← divide both sides by 3

        X = 114

first integer = 114

second integer = 114 + 1 = 115

third integer = 114 + 2 = 116

Therefore, the three consecutive integers are 114, 115, and 116.

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)