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Mathematics, 21.01.2020 14:31 sonicshon2

Ajar contains five red marbles and three green marbles. a marble is drawn at random and not
replaced. a second marble is then drawn from the jar. find the probability that the first marble is red and the second marble is green.

Answers

ansver
Answer from: kevin1015wangoudf1t
The jar starts out with 8 marbles in it. Five of them are red.
If you don't peek, the probability of drawing a red marble is

                 5/8 .

If you have already drawn a red marble on the first try, then
at that point, the jar has only 7 marbles in it, and three of them
are green.  Now, for your second draw, if you don't peek, the
probability of drawing a green marble is

                  3/7 .

The probability of BOTH of those events being successful is

               (5/8) x (3/7) = 15/56  =  approx 26.79% .
                
ansver
Answer from: Quest

-7

step-by-step explanation:

x^2 + 18x + 74 = (x + 9)^2 - 81 + 74

= (x + 9)^2 - 7.

so q = -7.

ansver
Answer from: Quest

eve and marks ratios are equivalent

step-by-step explanation:

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