In a zoo there are zebras and peacocks sharing the same area. there is a total of 14 zebras and peacocks. if you count, there is also a total of 36 legs. how many of each animal are there ? (15 points & brainliest answer to the first person ! ) : )

If we take the number of Zebras to be x and that of peacocks to be y
Then x + y = 14
A zebra has 4 legs while a peacock has 2 legs, 
Therefore the total number of legs will be 4x + 2y  which is equal to 36 .
Therefore, we have two equations 
    x + y = 14
   4x + 2y = 36    solving them simultaneously using elimination
   
4x +2y = 36
2x + 2y = 28 ( multiplying the first equation by 2 to eliminate y)
     2x = 8 ( subtracting the equations)
        x = 4  
       y = 14 -(4) 
          = 10
Therefore, there are 4 zebras and 10 peacocks in the zoo

The answer is 1 because you have to flip the sign when dividing by negative number and 3