Me with this set of 1.write an equation in point-slope form for the line that has a slope of 9/4 and contains the point (3, −4). 2. identify the equation in slope-intercept form for the line containing the points (3, 5) and (2, −5). 3. write an equation in slope-intercept form for the line perpendicular to y = −4x + 1 that passes through the point (−7, 1). 4. describe the transformation from the graph of f(x) to the graph of g(x). f(x) = 4x, g(x) = −4x 5. identify the equation that describes the line in slope-intercept form. slope = 3, point (−2, −4) is on the line

1. Y = 94x-39/4

2. Y = 10x-25

3. Y = 1/4x

4. Graph moves 8 units to the left

5. Y=3x+2

c. 27 units.

step-by-step explanation:

we are told that in circle a, ∠bae ≅ ∠dae.

we can see from our given diagram that in and ;

, as these are radii of our given circle.

therefore, by sas congruence postulate.

hence, side be will be equal to side de as corresponding parts of congruent triangles are congruent. so we can set an equation to find the value of x as:

now let us substitute x=17 in the expression for the length of be.

therefore, length of be will be 27 units and option c is the correct choice.