Brainliest answer will win asap! me! i really appreciate which graph shows a dilation of the triangle with a scale factor of 1/3? original triangle vertices : (0,0), (2,0) (2, -3) a. triangle with vertices: (0, 0), (2, 0), and (2, 3). b. triangle with vertices: (0, 0), (0.5, 0), and (0.5, negative 1). c. triangle with vertices: (0, 0), (6, 0), and (6, 9). d. triangle with vertices: (0, 0), (6, 0), and (6, negative 9).

Solution:

If a triangle has vertices (a,b), (p,q) and (c,d) then it's

Area= [a(q-d)-p(d-b)+c(b-q)] Square Units

Vertices of Preimage i.e Original Triangle = (0,0), (2,0) , (2,-3).

Area of Original Triangle = square units

As , given Dilation Factor =

Now, Dilation Factor < 1

So, Image will be smaller than pre-image.

Now, the area of Image, that is new Triangle=

Now, we will check by looking at the options Which Triangle has area of 1 Units.

Option A:  Triangle with vertices: (0, 0), (2, 0), and (2, 3).

Area of Triangle =   square units(Area is a positive Quantity)

Option B: Triangle with vertices: (0, 0), (0.5, 0), and (0.5, negative 1).

Area of Triangle =   square units

Option C :Triangle with vertices: (0, 0), (6, 0), and (6, 9).

Area of Triangle =   square units(Area is a positive Quantity)

Option D:  Triangle with vertices: (0, 0), (6, 0), and (6, negative 9).

Area of Triangle =   square units

None of the option matches the answer.

Now , it is not clear in the question whether original triangle or Image has been dilated by a factor of .

Original Triangle Vertices : (0,0), (2,0) (2, -3)

Dilation factor of image =

So, Dilation Factor of Preimage =3

So, to get the vertices of image i.e new triangle we have to multiply the vertices of original triangle by 3.

So, Coordinates of Vertices of Image = (0,0),(6,0),(6,-9)

Option C. Triangle with vertices: (0, 0), (6, 0), and (6, 9) is true.

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step-by-step explanation: