2x - 3y = -1 y = x - 1 solve for both x and y using elimination.

The solution for the system of equations 2x - 3y = -1 and y = x - 1 is:

x = 4, y = 3

The given system of equations is:

2x - 3y = -1(1)

y = x - 1(2)

Rearrange equation (2) to be in the same form as equation (1)

-x + y = -1(3)

Multiply equation (3) by 2

-2x + 2y = -2(4)

Add equations (1) and (3)

-y = -3

Multiply both sides by -1

y = 3

Substitute y = 3 into equation (2)

y = x - 1

3 = x - 1

x = 3 + 1

x = 4

Therefore the solution for the system of equations 2x - 3y = -1 and y = x - 1 is:

x = 4, y = 3

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answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: