Agame of “doubles-doubles” is played with two dice. if a player rolls doubles, the player earns 3 points and gets another roll. if the player rolls doubles again, the player earns 9 more points. how many points should the player lose for not rolling doubles in order to make this a fair game? mc011-1.jpg mc011-2.jpg mc011-3.jpg 1

solution:

one double = 5/ 36

two doubles = 1/36

no doubles = 1/6

in a standard form of equation, it will look like this:

12/36 + 5[(3-x)/36] - (5)(x/6) = 0

next, get the value of x, so this will give you the answer of 27/35 that is the probability of not rolling doubles.

can i see the following ?

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180