The function f(x)=3x+12x+11 can be written in vertex form as?

 y = -3(x - 2)^2 + 1 x-coordinate of vertex: x = -b/(2a) = -12/-6 = 2 y-coordintae of vertex: y(2) = -12 + 24 - 11 = 1 Vertex form: y = -3(x - 2)^2 + 1 Check. Develop y to get back to standard form: y = -3(x^2 - 4x + 4) + 1 = -3x^2 + 12x - 11. 

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