Fifty students were randomly selected to take part in a survey about their favorite school lunch. each student was allowed to only pick one item. the results are shown below. food item preferred number of students pizza 27 cheeseburger 14 salad bar 9 based on the information above, if the school served 500 lunches, how many pizzas can they expect to serve?

The expected number of pizza servings is 270.

Step-by-step explanation:

Food Item    Preferred Number of Students

pizza                 27

cheeseburger14

salad bar           9

Now we have been given that Fifty students were randomly selected to take part in a survey about their favorite school lunch. The school will be serving 500 lunches;

This means 10% of the total lunches or students were selected. So, if 27 students prefer pizza this means its 10 times will be needed for the whole lot making it pizzas.

Similarly, 140 cheeseburgers and 90 salad bars will be served making a tital of = lunches.

d. 24+-0.114

step-by-step explanation:

the question requires us to calculate the approximate 95% confidence interval for the mean number of ounces of ketchup per bottle in the sample given the following statistics;

sample mean = 24

standard deviation, σ = 0.4

sample size , n = 49

the confidence interval for a population mean is calculated using the formula;

sample mean ± z-score*(σ/sqrt(n))

the z-score associated with a 95% confidence interval, from the standard normal tables, is;

1.96

substituting these values into the formula;

24 ± 1.96*(0.4/7)

= 24 ± 0.112

from the alternatives given, choice d is closest to the above expression;