With this question, i need to make sure i'm right.

an=4n+1

Sum of first 30 terms

a1+a2+a30

 Sn=(a1+an)*n/2

a1first terms

an=last terma30

n= number of terms30

 calculation of a1

a1=4n+1=4*1+1=5

 calculation of an

a30=4*30+1=121

 S30=(a1+a30)*30/2

S30=(5+121)*30/2=1890

The sum of first 30 terms is 1890

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

homozygous. one is homozygous, while two is heterozygous.