The label on the cars antifreeze container claims to protect the car between -40c and 125c. to convert celsius temp to fahrenheit temperature, the formula is c= 5/9 (f-32). write and solve the inequality to determine the fahrenheit temperature range at which this antifreeze protects the car

 -40 °F ≤ θ ≤ 257 °F

EXPLANATION

Temperature range at which this antifreeze protects the car is -40 °C to 125 °C (in Celsius)

C= 5/9 (F – 32)

To make F the subject of the Formula

5/9(F – 32) = C

Multiply both sides of the equation by 9/5

5/9 * 9/5 (F – 32) = 9/5 · C

F – 32 = 9C/5

Add 32 to both sides of the equation

F – 32 + 32 = 9C/5 + 32

F = 9C/5 + 32 (Formula to convert from Celsius to Fahrenheit)

In Celsius, Lower limit, C = -40C

In Fahrenheit, Lower limit, F = 9C/5 + 32

= [9(-40/5)] + 32

= 9(-8) + 32

= -72 + 32

= -40 °F

In Celsius, Upper limit, C = 125C

In Fahrenheit, Upper limit, F = 9C/5 + 32

= [9(125/5)] + 32

= 9(25) + 32

= 225 + 32

= 257 °F

If the temperature is represented by θ,

Lower limit = -40 °F

⇒ θ must be not be less than -40 °F

⇒ θ must be greater than or equal to -40 °F

Mathematically, θ ≥ -40 °F

⇒ -40 °F ≤ θ

Also, Upper limit = 257 °F

⇒ θ must not be greater than 257 °F

⇒ θ is less than or equal to 257 °F

Mathematically, θ ≤ 257 °F

Combining the two statements of inequality, the Fahrenheit temperature range at which this antifreeze protects the car can be represented as:

-40 °F ≤ θ ≤ 257 °F

what's the question here?

we need to see the graph to know but

strong positive is if it is going up from left to right in a straight diagonal line (like this /)

strong negative is the same but from right to left (like this \)

weak negative is the same as strong negative but its more straight line still right to left

and weak positive is the same as strong positive but more a straight line still left to right though.