Aregular hexagon is dilated by a scale factor of 75 to create a new hexagon. how does the perimeter of the new hexagon compare with the original perimeter?

Let the length of the original hexagon be x:
the perimeter of the hexagon will be:
P=length*number of sides
P=6*x=6x
After the dilation the new length became:
length=scale factor × original length
=75 × x
=75x
thus the new perimeter will be:
6×75x
=450x
hence the new perimeter compared to the old one will be:
450x/6x
=75
the new perimeter is 75 times the old one

128/3reason being 5 and 1/3 = 16/316/3 • 2/3 = 32/31 and 1/3 = 4/3 32/3 • 4/3 this will equal 128/3