Find the average value of the function i = 15(1 - e1/2t) from t = 0 to t = 4. a. 7.5(3 - e-2) b. 7.5(1 + e-2) c. 7.5(2 - e-2) d. 7.5(2 + e-2)

1) Function:



2) Average = [value of the function a t = 0 + value of the function at t = 4 ] / 2

3) Value of the function at t = 0

15[1 - e^(0) ] = 15 [ 1 - 1] = 0

4) Value of the function at t = 4

15 [ 1 - e^ (4/2) ] = 15 [ 1 - e^(2) ]

5) Average

{ 0 + 15 [1 - e ^ (2) ] } / 2 = 7.5 [ 1 - e^(2)]

Given that all the options show e raised to negative 2, I guess you made a mistake on the function.

The major difference is that a histogram is only used to plot the frequency of score occurrences in a continuous data set that has been divided into classes, called bins.  bar charts, on the other hand, can be used for a great deal of other types ofvariables  including  ordinal  andnominal  data sets.