Mathematics, 20.09.2019 17:50 jerryG6171

Micheal and susan have a combined age of 17 years. micheal is 5 years older than susan

Answers: 2

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Let x be the unknown number which is the age of Susan

Susan's age: x
Michael's age: x + 5

Both total 17 years. The equation would be.

x + x + 5 = 17
2x + 5 = 17

Find x. Transfer 5 to the other side and change its sign
2x = 17 - 5
2x = 12

Find x. Divide both sides by 2.
2x / 2 = 12 / 2
x = 6 => Susan's Age.

Michael's age: x + 5 => substitute x by its corresponding value: 6 + 5 = 11.

To check.

Susan's Age + Michael's age = 17
6 + 11 = 17
17 = 17

Answer from: Quest

24/56=hx^7

step-by-step explanation:

Answer from: Quest

step-by-step explanation:

i found the life tables for the year 2012.

life table of males at age 30. probability of dying between ages x and x+1

total population:

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old.

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497

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Micheal and susan have a combined age of 17 years. micheal is 5 years older than susan...