Bob is a high school basketball player. he is a 70% free throw shooter. that means his probability of making a free throw is 0.70. during the season, what is the probability that bob makes his third free throw on his fifth shot? what is e(x)?

P =Probability of making free throw by Bob = 70 % = 0.70

Q=Probability that bob will be not able to make a free throw = 1 - 0.70= 0.30

Probability, that bob makes his third free throw on his fifth shot

                  = Taking fifth throw as free throw and Remaining 4 throws in which (two are free throw=P) and (2 are not free throw=Q)

          = ways

        = 6×Q²× P³

        = 6 × (0.30)²×(0.70)³

   e(x)  =  0.18522 (Approx)

there will be 35 boys in each team. : )

15%

step-by-step explanation:

use the table and count the number of guesses that has two correct answers.

the following are two correct answers

10010, 01100, 11000

a total of 3 numbers having 2 correct guesses out of 20 questions.

probability of getting 2 correct guesses = the number of questions getting 2 correct answers / total number of questions.

= 3/20

to convert it into percent multiply by 100, we get

= 3/20 * 100

= 15%

the answer is 15%

you.