Determine the discriminant for the quadratic equation –3 = x2 + 4x + 1. based on the discriminant value, how many real number solutions does the equation have? discriminant = b2 – 4ac real number solutions

-3 = x^2 + 4x + 1

0 = x^2 + 4x + 1 + 3

0 = x^2 + 4x + 4

Discriminant is b^2 - 4ac.

4^2 - 4(1)(4)

16 - 4(4)

16 - 16 = 0

Discriminant Rules:

1. If b²-4ac is negative, there are no real answers.
2. If b²-4ac is zero, there is one real answer.
3. If b²-4ac is positive, there are two real answers.

Based on rule 2, the answer is ONE REAL ROOT.

Ithink it’s d as the answer.