The heights of adult women are approximately normally distributed about a mean of 65 inches with a standard deviation of 2 inches. if rachael is at the 99th percentile in height for adult women, then her height, in inches, is closest to:

Using the normal distribution, it is found that her height is of 69.7 inches.

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In a normal distribution with mean and standard deviation , the z-score of a measure X is given by:

In this problem:

Her height is of 69.7 inches.

A similar problem is given at link

69.65 inches

Step-by-step explanation:

Mean =

Standard deviation =

Now we are supposed to find if Rachael is at the 99th percentile in height for adult women, then her height, in inches

Formula :

z at 99th percentile =2.326

Substitute the values in the formula

Hence her height is 69.65 inches .

85.560%

step-by-step explanation:

conditional probability is defined as:

p(a|b) = p(a∩b) / p(b)

in other words, the probability that a occurs, given that b has occurred = the probability that both a and b occur / the probability that b occurs.

in this example:

p(turns 64 | turns 44) = p(turns 64 & turns 44) / p(turns 44).

if someone turns 64, they must have already turned 44, so:

p(turns 64 | turns 44) = p(turns 64) / p(turns 44)

on page 42, we see that of the original 100,000, 94944 turn 44, and 81234 turn 64.   therefore:

p(turns 64 | turns 44) = 81234 / 94944

p(turns 64 | turns 44) = 0.85560