If a cube with a 5-in side length is sliced in half. what is the surface area of the two pieces? mr. bloop has a cylindrical water tank on his farm. it is ten feet long and 2 feet 9 inches in diameter. water flows out a valve in the bottom of the tank at a rate of 3.7 cubic feet per minute. at that rate, how long will it take to empty the tank when the tank is full? show work!

 Hello there!

1.) To start, first know that a cube has the same height, length, and width, meaning that all of the dimensions are 5-in. Then, when you slice it in half, this would mean that you have now reduced the width to half of its original. This would mean that the width is now 2.5 while the height and length remain 5.

Now that you have this information, you can now find the surface area by using this formula:

A= 2lw+2lh+2hw

Now plug in your values:

A=2(5)(2.5)+2(5)(5)+2(5)(2.5)

This would simplify to:

A=25+50+25

A=100 in squared

Therefore, the surface area of the two pieces are 100 inches squared.

2.) To start, first plug the measurements of the tank into the cylinder volume formula:

V=r^2h

V=(2.75)^2(10)

V= 237.58 cubic feet

Now, we must find how long it will take the tank to empty if the rate is 3.7 cubic feet per minute so divide the volume (in feet) by the rate:

237.58/3.7= 64.2108...

Rounded to the nearest hundredth, it would take approximately 64.21 minutes to empty the take when it is full.

:)

i don't even know man. edge inuity be messing with us. i had to ask a question too.

9) i can't see the angle so whatever it is just do this: cos(angle) x hypotenuse and then use that answer and they hypotenuse and plug it into this: (answer you just got)^2 + b^2 = (hypotenuse)^2. the first answer will be the answer of the adjacent side and the second answer after this equation will be the opposite side.

10) y = 14 x = √147 or 12.12435565

11) x = 4.8

12) x = 4.2

13) x = 9.3

14) pq: 13.2

qr : 17.6

angle p: 53º

15) angle c: 54.3º

angle a: 35.7º

16) h = 21040

v = 1841

step-by-step explanation:

10) 7/sin(30) = 14 = y

7^2 + b^2 = 14^2

49 + b^2 = 196

b^2 = 196 - 49

√b^2 = √147

x = √147

11) cos(70) x 14 = 4.788282007

x = 4.8

12) tan(25) x 9 = 4.196768923

x = 4.2

13) sin(31) x 18 = 9.270685348

x = 9.3

14) pq: sin(37) x 22 = 13.23993051

pq: 13.2

qr: cos(37) x 22 = 17.56998122

qr : 17.6

angle p: 180 - (37 + 90) = 53º

15) cos-1(7/12) = 54.31466529

angle c: 54.3º

angle a: 180 - (90 + 54.31466529) = 35.68533471

angle a: 35.7º

16) 4 x 5280 = 21120

cos(5) x 21120

h = 21039.63202

h = 21040

sin(5) x 21120

v = 1840.729287

v = 1841