Using the side lengths of pqr and stu which angle has a sine ratio of 4/5

.

Step-by-step explanation:

In triangle QRP

PQ= 20

PR=12

QR= 16

sinQ=

sinQ=

sinQ=

In triangle STU

SU=16

UT=34

ST=30

sinU=

sinU=

sinU=

sinT=

sinT=

sinT=

Hence, sinP=.

d.192

step-by-step explanation:

12*16=192

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b