Write an equation for a circle with a diameter that has endpoints at (–10, 1) and (–8, 5). round to the nearest tenth if necessary

The standard form for the equation of a circle is :

 So the midpoint of the diameter with endpoints at (−10,1)and(−8,5) is :

 ((−10+(−8))/2,(1+5)/2)=(−9,3)

 So the point (−9,3) is the center of the circle.

  Now, use the distance formula to find the radius of the circle:

  r^2=(−10−(−9))^2+(1−3)^2=1+4=5

 ⇒r=√5

 Subtituting h=−9, k=3 and r=√5 into EQ(1) gives :

 (x+9)^2+(y−3)^2=5

no i do not : ( what is it?

1. x> -5

2. x< 8

step-by-step explanation:

1. 2x> -10

divide by 2 from both sides of equation.

2x/2> -10/2

simplify, to find the answer.

-10/2=-5

x> -5 is the correct answer.

2. 3x< 24

divide by 3 from both sides of equation.

3x/3< 24/3

simplify, to find the answer.

24/3=8

x< 8 is the correct answer.

i hope this you, and have a wonderful day!