The width of a rectangle is 5 inches less than twice the length. the area of the rectangle is 700 square inches. which equation could be used to determine the length of the rectangle? a x2 - 5x = 700 b 2x2 - 5x - 700 = 0 c 2x2 - 5x + 700 = 0 d 2x2 + 5x = 700

Width:     W = 2L-5
area:      A = 700 sq in

A=L*W, so L = A/W.  Thus, L = (700 sq in) / (2L - 5 in)

Solve this for L.  Mult both sides of this equation by (2L-5), obtaining

L(2L-5) = 700.  Then, 2L^2 - 5L - 700 = 0

Using the quadratic formula to solve for L:

        -(-5) plus or minus sqrt( [-5]^2 - 4[2][-700] )
L =
                             2[2]
             
           5 plus or minus sqrt(25+5600)
    =
                                4
        5 plus or minus sqrt(5625)       5 plus or minus 75
    = =
                                  4                                   4

     = 20 or -17.5.  choose the positive result.  Thus, L = 20 inches, and 
                                                                      W = 2(20 in) - 5 in = 35 inches.

X> -2 is the simplified version.