Joe has eaten 2/5 of a pizza. jane has eaten 1/8 of a pizza how many times more pizza has joe eaten than jane

Well, the first thing you would do is find like denominators for each fraction.

Since the smallest common term between the two is 40, that will be your denominator for each. Then you would multiply the numerator by the number your denominator was multiplied to get to 40. So, you would end up with 16/40 because 5*8=40 and 2*8=16 and 5/40 because 8*5=40 and 1*5=5.

After that, you would just subtract them.

16/40 - 5/40 = 11/40 and as a decimal that is 0.275. So, Joe has eaten 0.275 more pizza than Jane.

Hope this helps! :)

geometric series converge the common ratio r has magnitude less than one.

which is equivalent to

for the example we need

|2-x| < 1

-1 < 2-x   and 2-x < 1

x < 3 and x > 1

we can write that

answer: 1 < x < 3

1a. common ratio r=250/25=10 > 1     diverges

1b.   r=50/100=1/2 converges

when these converge they converge to

where a is the first term.

answer: 200

1c. r=-1   so it's not the case that |r| < 1.     diverges

2a. x is the common ratio so we converge when |x|< 1

2b.   r=-10x / -2 = 5x.

we converge when

|5x| < 1

|x| < 1/5

2c.   r=3-2x

-1 < 3-2x and 3-2x < 1

-4 < -2x and 2 < 2x

x < 2 and 1 < x

1 < x < 2

2d. [/tex] r=-48x^3/12 = 4x^3[/tex]

|4x^3| < 1

|x^3| < \frac 1 4

|x| < 4^{-1/3}