What is the equation of the line perpendicular to 2x+y=0 that passes through the point (2,2) y=-2x+6 y=-1/2x+3 y=1/2x+1 y=2x-2

2x + y = 0
y = -2xthe slope here is -2. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal slope, flip the original slope and change the sign. So we have slope -2 or -2/1flip it and it becomes -1/2change the sign and it becomes 1/2. So ur perpendicular line will have a slope of 1/2.

y = mx + b
slope(m) = 1/2
(2,2)x = 2 and y = 2
now sub and find b, the y int
2 = 1/2(2) + b
2 = 1 + b
2 - 1 = b
1 = b
so ur perpendicular equation is : y = 1/2x + 1 <===

paul's with a y-intercept of $ 2856