How much material is needed to construct a triangular tent that is 24 feet wide, 5 feet tall, and 20 feet long with side measurements of 13 feet? 816 square feet 1024 square feet 1120 square feet 1392 square feet

The answer is " 1120 square feet. ".
Total surface area of a triangular prism = width x height +(sum of sides + width) x length and here;
width = 24
height = 5
sides = 13
length = 20
= (24 x 5) + (13 + 13 + 24) x 20
= 120 + (50 x 20)
= 120 + 1000
= 1120 square feet. 

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