The equation of the line passing through the points (2,-5) & (3,-1)

Y = mx + b

m is the slope and b is the y intercept

to find the slope with two points given, you subtract the two y values over the two x values (y-y) / (x-x)

-5 - (-1) = -4
2 - 3 = -1

-4 / -1 = 4
m = 4

Now to find b, you plug in a value of x and a value of y that you already know.
-5 = 4(2) + b
-5 = 8 + b
-13 = b

y = 4x - 13

[B] 4x - y = 13
- y = -4x + 13
y = 4x - 13

I'm pretty sure it's b). i try drawing the functions out and b is the one that stands out or isnt a "line"