Alan participated ina car race in which he had to cover a distance of at least 50 kilometers. he had fuel in his car for a maximum distance of 53 kilometers. if the distance is given by s (t) = 3t + 47, where t is the time in hours, find the minimum and maximum number of hours for which alan can drive his car.

This problem has more holes than swiss cheese.

ASSUME that the time he drives only depends on the distance he covers,
and has nothing to do with his speed or how he drives.

The race rules say he has to cover at least 50 km,
so the minimum time he can drive is the solution to
[ 50 = 3t + 47 ]
Subtract 47 from each side:
3 = 3t
Divide each side by 3 :
1 = t minimum

He has fuel for exactly 53 km, so the maximum time
he can drive is the solution to
[ 53 = 3t + 47 ]
Subtract 47 from each side :
6 = 3t
Divide each side by 3 :
2 = t maximum