Let sin(67°) = 0.9205.   enter the smallest positive value for the angle measure (θ), in degrees, for cos(θ) = 0.9205.

θ = 23 degrees

Step-by-step explanation:

We know that (I)

We also know that cos(θ) = 0.9205 (II)

Because the angle 67 degrees is less than 90 degrees we can use the complementary angles equations

The equations are :

cos (θ) = sin ( 90° - θ )     (III)

sin (θ) = cos ( 90° - θ )     (IV)

tg (θ) = cotg ( 90° - θ )     (V)

We can use the equation (III) to find the angle.

If we equalize (I) and (II) :

⇒

cos(θ) = sin(67)

Now, If we use the equation (III) :

cos(θ) = sin(67) = sin ( 90° - θ ) ⇒

67 ° = 90 ° - θ

θ = 23 °

We find that the angle θ is 23 °

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1

70

step-by-step explanation:

2*5=10

4*15=60

60+10=

70