Amirror frame in the shape of an oval is shown below. the ends of the frame form semicircles: an oval is formed by a rectangle with semicircles at each end. the length of the rectangle is 60 inches. the width of the rectangle is 27 inches. which of the following is the perimeter of the inner edge of the frame? (π = 3.14) 343.56 inches 289.56 inches 258.78 inches 204.78 inches pl halp

The perimeter of inner edge of frame is:

                         204.78 inches.

Step-by-step explanation:

We are given length(L) of rectangle=60 inches.

Width(W) of rectangle=27 inches.

We know that the inner edge of the frame is comprised of the two length of the rectangle and 2 semicircles.

We know that the width of the rectangle is equal to the diameter of semicircle.

Hence,Radius(r) of semicircle=W/2

                                            = 27/2 inches

Hence, Perimeter of 1 semicircle=π×r

As there are 2 semicircles.

Hence, Perimeter of 2 semicircle=2×π×r

                                                      =2×3.14×(27/2)

                                                     = 84.78 inches.

Hence, the perimeter of inner edge of frame is:

2×Length of rectangle+Perimeter of 2 semicircle.

= 2×60+84.78

= 204.78 inches.

he used the algebra tiles correctly.

step-by-step explanation:

given : 3x(2x-1)

solution :

since he used algebra tiles .

armando's solution is the same in the solution shown in figure

as he distributed 2x into x and x and wrote them vertically

and also write   -1 vertically

and 3x into x and x and x and wrote it horizontally

performing the multiplication in the algebra tiles we get

and solving the given expression :

3x(2x-1)

since solving the expression using tiles   and solving the expression algebraically we get the same answer

thus   we can choose the first statement as the answer to this problem which is "he used the algebra tiles correctly".

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step-by-step explanation: