In δabc, m∠cab = 60° and ad is an angle bisector with d ∈ bc and ad = 8 ft. find the distances from d to the sides of the triangle.

The answer is 4 feet.
Draw a line segment from D perpendicular to AC and intersect AC at F.
triangle ADF is a right triangle, with angle AFD=90, Angle DAF=half of BAC=30
in a 30-60-90 triangle, the shortest side is half of the hypotenuse. the hypotenuse AD=8, so DF=4
Draw a line segment perpendicular from D to AB and intercept AB at E.
DE is also 4 feet, same as above.