7x - 3y = 4 2x - 4y = 1 which of the following system of equations is not equal to the system of equations shown above? a.28x - 12y = 16 and -6x + 12y = -3 b.14x - 6y = 4 and -14x + 28y = 1 c.-28x + 12y = -16 and 28x - 56y = 14

Option B

Step-by-step explanation:

The given equations are 7x - 3y = 4 (1) and 2x - 4y = 1 (2)

Option A : we multiply equation (1) by 4 then

28x - 12y = 16 (3)

We multiply equation (2) by (-3) then we get.

-6x + 12y = -3 (4)

Equation 3 and 4 are similar as 1 and 2 .

Therefore, option A is correct represent similar equations.

Option B : By multiplication equation (1) by 2

14x - 6y = 8

and multiplication equation (2) by (-7)

-14x + 28y = (-7) (Therefore, equations does not match the system of equation)

Option C : If we multiply equation (1) by (-4)

-28x + 12y = -16

and multiply equation (2) by 14 we get.

28x - 56y = 14

These equations are similar to system of equations.

Therefore, Option B is the answer.

0.02040816326

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!