Mathematics, 30.07.2019 07:40 azaz1819

Here are my steps: u(t)=t+(uo-t)e^kt where k< 0 300=70+(450-70)e^5k 300=70+(380)e^5k 230=380e^5k e^5k=23/38 5k lne= 23/38 k=ln 23/38/5 k=-.1004183888 230=70+380e^5k 380e^5k=160 e^kt=8/19 kt=ln 8/19 kt/k=ln 8/19/k t=8.6 minutes. 8.6 minutes + 5 minutes initial cooling time = 5: 13 pm.

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Here are my steps: u(t)=t+(uo-t)e^kt where k< 0 300=70+(450-70)e^5k 300=70+(380)e^5k 230=380e^5...