The number of students enrolled in a new course as a function of time can be represented by the function. f(x)=(4)^x −1 what is the average increase in the number of students enrolled per hour between hours 2 and 4? enter your answer in the box.

is there a 120 if so i took  the test

Step-by-step explanation:

120

Step-by-step explanation:

We are given that the function for the number of students enrolled in a new course is .

It is asked to find the average increase in the number of students enrolled per hour between 2 to 4 hours.

We know that the average rate of change is given by,

,

where f(x)-f(a) is the change in the function as the input value (x-a) changes.

Now, the number of students enrolled at 4 = f(4) = = 255 and the number of students enrolled at 2 = f(2) = = 15

So, the average increase = = = 120.

Hence, the average increase in the number of students enrolled is 120.

here you hope this .

step-by-step explanation:

hypotenuse = √(15² + 8²)

=  √(225 +64)

=  √(289) = 17

sin(x) = cos(y) = 8/17

they are identical so long as you are doing the sine of one angle and the cosine of the only other angle that isn't the right angle.

4/6 = 2/3

so it should take 3/3 hours per man. so 9 hours is the answer 3*3 =9

step-by-step explanation: