Aparticle moves with velocity function v(t) = 2t2 - 3t - 3, with v measured in feet per second and t measured in seconds. find the acceleration of the particle at time t = 2 seconds. (4 points) a. 3/4 ft/s^2 b. -1 ft/s^2 c. 32ft/s^2 d. 5 ft/s^2

d. 5 ft/s^2

Step-by-step explanation:

The acceleration is the derivative of the velocity.

In this problem, we have the velocity function

So the acceleration function is:

.

Find the acceleration of the particle at time t = 2 seconds

This is a(2). So:

.

The correct answer is

d. 5 ft/s^2

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step-by-step explanation:

1+2+3+4+5+6+7+8+9+10 = 55

2*10 = 20

55-20 = 35

to find the perimeter of the rectangle this is the expression:

x-9+x-9+3x-4+3x-4=138

if we simplify it:

8x-26=138

remember, 138 is what it all adds up to

the length is 11.5cm

the width is 57.5cm

the area is 661.25cm^2

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