Mathematics, 21.08.2019 15:10 patriots2833
2700=2300(1+r)^5 solve for r show all work
Answers: 1
![2700=2300(1+r)^5\\ \\ (1+r)^5=\frac{2700}{2300}\\ \\ (1+r)^5=\frac{27}{23}\\ \\ \sqrt[5]{(1+r)^5}= \sqrt[5]{\frac{27}{23}}\\ \\ 1+r= 1.032\\ \\ r=1.032-1\\ \\ \boxed{r=0.032}](/tpl/images/0185/0354/9da39.png)
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