Suppose that θ is an angle in standard position whose terminal side intersects the unit circle at (-7/25,24/25) . find the exact values of cotθ ,cos θ ,cscθ

cot θ = -7/24 cos θ = -7/25 csc θ = 25/24 Given that the intersection is at (-7/25, 24/25) that immediately gives you sine and cosine. So by definition: sin θ = 24/25 cos θ = -7/25 Since the cotangent is cosine over sine (the reciprocal of tangent) we get: cot θ = (-7/25) / (24/25) = (-7/25) * (25/24) = -7/24 And since cosecant is the reciprocal of sine, we get: csc θ = 1/(24/25) = 1 * 25/24 = 25/24

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