An alloy is 70% iron. how much of this alloy do you need if you want to obtain 50 7/20 lb of iron?

72 lb

Step-by-step explanation:

An alloy is 70% iron, that is, there are 70 lb or iron every 100 lb of the alloy. This is our conversion factor. In order to find out how much allow is required to obtain 50 7/20 lb (50.35 lb) of iron, we will use proportions.

50.35 lb iron × (100 lb alloy/70 lb iron) = 72 lb alloy

We will need 72 lb of the alloy.

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

i don't think there is enough