The graph illustrates a reflection of angel qpr what line is angel qpr reflected across to create q'p'r'

The line y =x  across  which angle QPR is reflected  to create Q'P'R'.

Step-by-step explanation:

We are given that  a triangle PQR whose vertices are P is at (1,-4),Q at (2,-2) and R at (4,-5).

The image of triangle PQR is triangle P'Q'R'  obtained after reflection.

The coordinates of P' is (-4,1).

The coordinates of Q' is (-2,2).

The coordinated of R' is (-5,4).

We have to find the line that is angle QPR reflected across to create Q'P'R'.

We can see that the transformation rule is given by

Therefore, the reflection line y=x across which angle QPR is reflected to create Q'P'R'.

y=x

go hook jvc hgv cj xk jvc 6756

step-by-step explanation:

there is a formula i can give you:

it is r^2*n*sin(360/n) divided by 2 where r represents the "radius" and n is the number of sides.

plug them in:

(10sqrt(3))^2*6*sin(360/6) divided by 2

100*3*6*sin(60) divided by 2

900*sin(60)

900*sqrt(3)/2

450*sqrt(3)

approx is 779.4 cm^2