What are the possible rational zeros of f(x) = x4 + 2x3 − 3x2 − 4x + 20? (1 point) a.) 1, 2, 4, 5, 10, 20 b.) ± 1, ± 2, ± 3, ± 4, ± 5, ± 6, ± 7, ± 8, ± 9, ± 10, ± 11, ± 12, ± 13, ± 14, ± 15, ± 16, ± 17, ±18, ± 19, ± 20 c.) ± 1, ± 2, ± 4, ± 5, ± 10, ± 20 d.) 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20

The possible rational zeros of polynomial function could be only among the divisors of the free term of this polynomial function.

The free term is 20 and the divisors of 20 are:

correct choice is C

there is no grid

step-by-step explanation:

step-by-step explanation:

if you want to separate 54 into 6 individual tiers then you need to divide if you want to separate 54 into 6 individual tiers then you need to divide 6 and 54.

if you divide 9 by 6 you will get 54.

- hope i .