Lynn takes her puppy, olive, to a doggy daycare. the price for the daycare is $21 per day along with a monthly admission fee of $48. last month lynn paid a total of $426. which equation can be used to find the number of days, d, that olive spent at daycare, and how many days was she there? 48d + 426 = 21; 9 days 21d + 48 = 426; 18 days 48d + 21 = 426; 8 days 426d - 21 = 48; 7 days nextreset

Option B. 21d + 48 = 426

18 days

Step-by-step explanation:

Lynn takes her puppy, Olive to a doggy daycare.

The price for the daycare = $21 per day

Monthly admission fees = $48.00

Last month Lynn paid a total = $426.00

Let the number of days that Olive spent at daycare be 'd'

So the equation will be

21d + 48 = 426

21d = 426 - 48

21d = 378

d =

d = 18 days

Olive spent 18 days at daycare and the equation can be used to find the number of days is Option B. 21d + 48 = 426

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.