Use lagrange multipliers to find the point on the plane x − 2y + 3z = 6 that is closest to the point (0, 2, 5).

The point on the plane x − 2y + 3z = 6 that is closest to the point (0, 2, 5) is.

Let (x,y,z) be the point on the plane x − 2y + 3z = 6 that is closest to the point (0, 2, 5).Then

The gradient of f and g are

Δ=

Δ

Setting Δf=kΔg

k(1,-2,3)

2x=k,2(y-3)=-2k,2(z-5)=3k

Solving we get the point

Therefore the point on the plane x − 2y + 3z = 6 that is closest to the point (0, 2, 5) is.

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answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

i would be happy to . most people on would also love to i'm sure. if you just want someone who has done algebra before and want a little more personal relationship than just begging strangers for , i can certainly be of service. i do have college myself so i might not be 24/7.