Asock drawer has 8 blue socks and 6 black socks. if i randomly select two socks, one at a time, what is the probability i will first get a blue sock and then, without replacing it, a black sock? a. 24/91 b. 2/7 c. 6/81 d. 4/13

Calculate first the total number of permutation possible.

You select two socks so that will be:

14⋅13=182

Now you must first select a blue sock then a black sock:

You can only pick 8 possible blue socks
You can only pick 6 possible black socks

which means that this permutation (blue→black) have 8⋅6=48 possibilities for each different blue and black sock.

express in fraction:

48182=2491

75 tickets have been sold so far.

step-by-step explanation:

in this question it is clearly mentioned that 45 children's tickets have been sold and this number is 60% of the total tickets sold.

now let's assume the total number of tickets sold be x.

then 60% of x = 45

⇒

⇒ x(.6) = 45

by dividing with .6 on both the sides of the equation

⇒ x = 75

therefore 75 tickets have been sold so far.

what is all that apply?